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The perimeter of a rectangle is 48 feet. if the length is thrice its width, find the dimensions of tge rectangle

Answers

  • Réponse publiée par: elishakim80

    dimension is 6×18 feet

    48 = 2L + 2W

    L = 3W

    therefore;

    48= 2(3W) + 2W

    48= 6W + 2W

    48= 8W

    W= 6

    and

    L = 3W

    L= 3(6)

    L= 18

    to prove :

    48= 2(18) + 2(6)

    48= 36+ 12

    48=48

  • Réponse publiée par: kurtiee
    18 ft × 6 ft

    Step-by-step explanation:

    Let x be the width and 3x the length.

    Getting the width.

    P = 2L × 2W

    48 = 2(3x) + 2(x) \\ 48 = 6x + 2x \\ 48 = 8x \\  \frac{48}{8}  =  \frac{8x}{8}  \\ 6 = x

    Getting the length.

    3x = 3(6) = 18

    Check:

    P = 2L + 2W

    48 = 2(18) + 2(6 \\ 48 = 36 + 12 \\ 48 = 48

    Correct!

  • Réponse publiée par: elaineeee
    23 green
    52 red
    34 blue
    61 yellow
    30 pink.
    since we are looking to the percentage of red. so we need to do is the no if red gumballs over the total number of gumballs
    52/23+52+34+61+30
    52/200
    21/100 or 21 %
  • Réponse publiée par: elaineeee

    in mathematics, the graph of a function f is, formally, the set of all ordered pairs (x, f( and, in practice, the graphical representation of this set. if the function input x is a real number, the graph is a two-dimensional graph, and, for a continuous function, is a curve.

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The perimeter of a rectangle is 48 feet. if the length is thrice its width, find the dimensions of t...