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• 1.choose the prime number. a.) 13b.) 21c.) 33d.) 6...

1.choose the prime number. a.) 13b.) 21c.) 33d.) 692. choose the greatest common divisor or gcd of 96, 39, and 42.a.)3b.)6c.)7d.)9❤good luck❤​

1. a) 13

2. a) 3

Step-by-step explanation:

1. choose prime numbers

note: prime numbers are  whole number greater than 1 whose only factors are 1 and itself.

in 13 its factor is only 1 and itself ( so its a prime number)

in 21 its factor are  1 and itself, 3 and 7 ( so not a prime number)

in 33 its factor are 1 and itself, 3 an 11( so not a prime number)

in 69 its factor are 1 and itself, 3 and 12... ( so not a prime number)

so its letter a

2. GCD

96,39 and 42 its  greatest common divisor is 3

so its letter a

• Réponse publiée par: 09389706948

1. true

5. true

6. true

15. false

16. true

17. false

18. false

20. true

DI KO NA ALAM YUNG SA IBA..HOPE THAT IT WILL HELP YOU

• Réponse publiée par: alexespinosa

120

Step-by-step explanation:

10-10,20,30,40,50,60,70,80,90,100,110,120

40-40,80,120

60-60,120

• Réponse publiée par: villatura

120

Step-by-step explanation:

8-8,16,24,32,40,48,56,64,72,80,88,96,104,112,120

24-24,48,72,96,120

40-40,80,120

• Réponse publiée par: nelspas422

GAMITIN MO UTAK MO WAG KA UMASA DITO

• Réponse publiée par: shannel99

Greatest Common Factor and Least Common Multiple

The product of the three numbers is 3, 240.

Step-by-step explanation:

To find for the three numbers, consider the following condition: (1.) the GCF is 6 and (2.) the LCM is 270.

Condition 1:

If the GCF = 6 then the number must be divisible by 6, by listing method numbers divisible by 6 are 6, 12, 18, 24, 30, 36.

Condition 2:

The LCM should be 270 thus 270 ÷ 6 = 45, therefore 270 is a multiple of 6 by 45 times.

If the GCF of 6 is 6 and 270 is a multiple of 6 by 45 times then the first number must be 6.

Now, consider 12, the factors of 12 are {1,2,3,4,6,12}. Given that the three numbers should have 6 as the GCF then 12 could possibly be the second number. However, if we divide 270 by 12, the quotient is not an exact number thus it will not satisfy the second condition since 270 is not a multiple of 12.

Consider 18. The factors of 18 are {1,2,3,6,9,18}. Given that the three numbers should have 6 as the GCF then 18 could possibly be the second number. Let us see if 270 is a multiple of 18 thus 270 ÷ 18 = 15. Therefore, the second number is 18 since 6 and 18 have GCF equal to 6 and they both have LCM of 270.

Next, consider the number 24. The factors of 24 are {1,2,3,4,6,8,12,24}. Given the condition that the number should have a GCF of 6 in relation with the first and second number then 24 could possibly be the third number. However, 270 is not a LCM of 24 since 270 ÷ 24 is not an exact number and it will not satisfy the second condition.

Let us move on with 30. 30 have factors {1,2,3,5,6,10,15,30}. Both 6, 18, and 30 have GCF of 6 that might satisfy the first condition. Check if 270 is a LCM of 30 such that 270 ÷ 30 = 9 thus 30 is the third number which has a GCF of 6 and LCM of 270.

Multiplying the three numbers will give (6)(18)(30) which is equal to (108)(30) which again is equal to 3, 240.

• Réponse publiée par: hannahleigh

how do you find LCM?

Step-by-step explanation:

Step 1: Write the given numbers in a horizontal line, separating them by commas.

Step 2: Divide them by a suitable prime number, which exactly divides at least two of the given numbers.

goodluck

• Réponse publiée par: homersoncanceranguiu

LCM is a fraction greater than both the fractions or equal to one or both of them (when both fractions are equal). When you take the LCM of the numerator and GCFof the denominator, you are making a fraction greater than (or equal to) the numbers. There has been a simple method to find the G.C.D. of fractions.

• Réponse publiée par: shannel99