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Find the x-intercept.
y=x^3 + 2x^2 + 11x-2

Answers

  • Réponse publiée par: rhaineandreirefuerzo

    -2

    Step-by-step explanation:

    x=0

    y=(0)^3+2(0)^2+11(0)-2

    y=0+2(0)+0-2

    y=0+0+0-2

    y=-2

  • Réponse publiée par: kuanjunjunkuan

    X=2,Y=6

    Step-by-step explanation:

  • Réponse publiée par: sherelyn0013

    a.       As x decreases without bound, the graph of the polynomial function either falls or rises to the left continuously without end.


    b.      The graph is (i) above the x-axis and (ii) below the x-axis in the following intervals:

    1.       (i)-3/2<x<1 and x>4;               (ii) x<-3/2 and 1<x<4

    2.       (i) x<-3 and 1<x<4; (ii) -3<x<1 and x>4

    3.       (i) x<-5 and -1<x<1 and (ii) -5<x<-1 and 1<x<5

    4.       (i) -5<x<-2 and x<-5, -2<x<1 and x>1

    5.       (i) x<-3 and x>1 (ii) -3<x<-1, -1<x<0, and 0<x<1


    c.       As x increases without bound, the graph of the polynomial function either falls or rises to the right continuously without end.


    d.      The leading terms of the polynomial function are the following:

     1.) 2 x^{3}             2.) -x^{3}                 3.) x^{4}                     4.) - x^{4}               5.) x^{10}


    e. The leading coefficients and degree:

    1.) Leading coefficient:2, degree: 3

    2.) Leading coefficient:-1, degree: 3

    3.) Leading coefficient: 1,  degree: 4

    4.) Leading coefficient: -1, degree: 4

    5.) Leading coefficient: 1, degree: 10

     

     

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Find the x-intercept.y=x^3 + 2x^2 + 11x-2...