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Name the vertex, axis of symmetry, focus, directrix, end points of latus rectum, and directum of opening of the whose equation is given. ()

4(y-2) = (x-4) {}^{2}
y \:  = {x}^{2} + 4 \times + 1

Answers

  • Réponse publiée par: elaineeee

    answer:

    given: 4(y-2)=(x-4) squared

    v: (h, k) (4,2)

    aos: x=h ; x=4

    focus: (h, k+c) (4,2+4)= (4,6)

    c=4

    directrix: y=k-c ; y=2-4 ; y= - 2

    ends of lr: (h+/- 2c,k+c); (4+/-2(4), 2+4); (12,6) and (-4,6)

  • Réponse publiée par: 123gra

    answer:

    Step-by-step explanation:

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Name the vertex, axis of symmetry, focus, directrix, end points of latus rectum, and directum of ope...