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The sum of the digits of a two-digit number is 14. twice the tens digit increased by two equals four times the units digit. find the number

Answers

  • Réponse publiée par: homersoncanceranguiu

    answer:

    the number is 95

    step-by-step explanation:

    let

    x = tens digity = units digit

    expressions

    "the sum of the digits of a two-digit number is 14"x+y=14twice the tens digit increased by two equals four times the units digit2x+2=4y

    solve

    derive the 1st equationy=14-xsubstitute the value of y .

    2x+2=4(14-x)

    distributive property

    2x+2=56-4x

    2x+4x=56-2

    6x = 54

    divide by 6

    x = 9 tens digit

    y=14-x = 14-9 = 5

  • Réponse publiée par: kuanjunjunkuan

    Step-by-step explanation:

    1. let 1 st no. be 8x

    2nd no. be 3x

    8x + 3x = 143  \\  11x = 143 \\ x =  \frac{143}{11}  \\ x = 13

    the no. is 13

    1st no. is 8x = 8×13=104

    2nd no. is 3x= 3×13=39

    Hope it helps

  • Réponse publiée par: villatura

    answer:

    a.1 foot

    b.0.33 (not sure) but 3feet=1 yard

    c.36 inches

    hope it !

  • Réponse publiée par: kuanjunjunkuan

    \frac{2}{3 {x}^{2}  {y}^{4}  {z}^{4} }

    Step-by-step explanation:

    ( \frac{3 {x}^{ - 1} {y}^{2}  {z}^{3}  }{2 {x}^{ - 3} {y}^{ - 2}   {z}^{ - 1} }  {)}^{ - 1}

    Given by the rule

    {x}^{ - n}  =  \frac{1}{ {x}^{n} }

    First simplify the outermost exponent

    ( \frac{2 {x}^{ - 3}  {y}^{ - 2} {z}^{ - 1}  }{3 {x}^{ - 1}  {y}^{2} {z}^{3}  } )

    Then the inner ones

    {x}^{ - 3}  =  \frac{1}{ {x}^{3} }

    {y}^{ - 2}  =  \frac{1}{ {y}^{2} }

    {z}^{ - 1}  =  \frac{1}{z}

    \frac{1}{  {x}^{ - 1}  }=   \frac{1}{ \frac{1}{x} }   = x

    Then

    \frac{2x}{3 {x}^{3}  {y}^{2} {y}^{2}  {z}^{3}  z}

    \frac{2x}{3 {x}^{3}  {y}^{4}  {z}^{4}}

    Simplify x

    \frac{2}{ 3{x}^{2}  {y}^{4} {z}^{4}  }

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The sum of the digits of a two-digit number is 14. twice the tens digit increased by two equals four...