Confidence interval for the population mean z-test or normal distribution solution: given: n=20, x̄ =89, s=2.0, 99% formula: x̄ -z_alpha/2(s/square root of n)< µ< x̄ +z_alpha/2(s/square root of n) 89-(2.575)(2.0/square root of 20)< µ< 89-(2.575)(2.0/square root of 20) 87.848< µ< 90.152
margin of error: solution: the critical value is 2.575. the standard deviation is 2.0 (from the question), but as this is a sample, we need the standard error for the mean. the formula for the se of the mean is standard deviation / √(sample size), so: 2.0/ √(20)=0.447. me=2.575 * 0.447 = 1.151.
therefore, the margin of error is 1.151 with the confidence interval of 87.848< µ< 90.152.
so 1 peson = 40 hours
now for the moment of truth
the answer is 3. repeating hours
but we can still solve it cuz we are talking bout' time
so if 40/12 is 3 and three is the remainder
and the closest multiple is 48
48-40=8
8 of 12 is 66.
or 2/3 of 100
so 2/3 in minutes is 40
so the answer is 3 hours and 40 minutes
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z-test or normal distribution
solution:
given:
n=20, x̄ =89, s=2.0, 99%
formula:
x̄ -z_alpha/2(s/square root of n)< µ< x̄ +z_alpha/2(s/square root of n)
89-(2.575)(2.0/square root of 20)< µ< 89-(2.575)(2.0/square root of 20)
87.848< µ< 90.152
margin of error:
solution:
the critical value is 2.575.
the standard deviation is 2.0 (from the question), but as this is a sample, we need the standard error for the mean.
the formula for the se of the mean is standard deviation / √(sample size), so: 2.0/ √(20)=0.447.
me=2.575 * 0.447 = 1.151.
therefore, the margin of error is 1.151 with the confidence interval of 87.848< µ< 90.152.
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